-3y^2-7y-4=0

Solution for -3y^2-7y-4=0 equation:

-3y^2-7y-4=0

a = -3; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·(-3)·(-4)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*-3}=\frac{6}{-6}
=-1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*-3}=\frac{8}{-6}
=-1+1/3
$